消消乐的构成主要包括三部分：游戏主体、计分器、计时器，下面来看一下具体实现。
先来看一下游戏所需 Python 库。
import os import sys import time import pygame import random
定义一些常量，比如：窗口宽高、网格行列数等，代码如下：
WIDTH = 400 HEIGHT = 400 NUMGRID = 8 GRIDSIZE = 36 XMARGIN = (WIDTH - GRIDSIZE * NUMGRID) // 2 YMARGIN = (HEIGHT - GRIDSIZE * NUMGRID) // 2 ROOTDIR = os.getcwd() FPS = 30
接着创建一个主窗口，代码如下：
pygame.init()
screen = pygame.display.set_mode((WIDTH, HEIGHT))
pygame.display.set_caption('消消乐')看一下效果：
再接着在窗口中画一个 8 x 8 的网格，代码如下：
screen.fill((255, 255, 220)) # 游戏界面的网格绘制 def drawGrids(self): for x in range(NUMGRID): for y in range(NUMGRID): rect = pygame.Rect((XMARGIN+x*GRIDSIZE, YMARGIN+y*GRIDSIZE, GRIDSIZE, GRIDSIZE)) self.drawBlock(rect, color=(255, 165, 0), size=1 # 画矩形 block 框 def drawBlock(self, block, color=(255, 0, 0), size=2): pygame.draw.rect(self.screen, color, block, size)
看一下效果：
再接着在网格中随机放入各种拼图块，代码如下：
while True: self.all_gems = [] self.gems_group = pygame.sprite.Group() for x in range(NUMGRID): self.all_gems.append([]) for y in range(NUMGRID): gem = Puzzle(img_path=random.choice(self.gem_imgs), size=(GRIDSIZE, GRIDSIZE), position=[XMARGIN+x*GRIDSIZE, YMARGIN+y*GRIDSIZE-NUMGRID*GRIDSIZE], downlen=NUMGRID*GRIDSIZE) self.all_gems[x].append(gem) self.gems_group.add(gem) if self.isMatch()[0] == 0: break
看一下效果：
再接着加入计分器和计时器，代码如下：
# 显示得分
def drawScore(self):
score_render = self.font.render('分数:'+str(self.score), 1, (85, 65, 0))
rect = score_render.get_rect()
rect.left, rect.top = (55, 15)
self.screen.blit(score_render, rect)
# 显示加分
def drawAddScore(self, add_score):
score_render = self.font.render('+'+str(add_score), 1, (255, 100, 100))
rect = score_render.get_rect()
rect.left, rect.top = (250, 250)
self.screen.blit(score_render, rect)
# 显示剩余时间
def showRemainingTime(self):
remaining_time_render = self.font.render('倒计时: %ss' % str(self.remaining_time), 1, (85, 65, 0))
rect = remaining_time_render.get_rect()
rect.left, rect.top = (WIDTH-190, 15)
self.screen.blit(remaining_time_render, rect)看一下效果：
当设置的游戏时间用尽时，我们可以生成一些提示信息，代码如下：
while True: for event in pygame.event.get(): if event.type == pygame.QUIT: pygame.quit() sys.exit() if event.type == pygame.KEYUP and event.key == pygame.K_r: flag = True if flag: break screen.fill((255, 255, 220)) text0 = '最终得分: %s' % score text1 = '按 R 键重新开始' y = 140 for idx, text in enumerate([text0, text1]): text_render = font.render(text, 1, (85, 65, 0)) rect = text_render.get_rect() if idx == 0: rect.left, rect.top = (100, y) elif idx == 1: rect.left, rect.top = (100, y) y += 60 screen.blit(text_render, rect) pygame.display.update()
看一下效果：
说完了游戏图形化界面相关的部分，我们再看一下游戏的主要处理逻辑。
我们通过鼠标来操纵拼图块，因此程序需要检查有无拼图块被选中，代码实现如下：
def checkSelected(self, position): for x in range(NUMGRID): for y in range(NUMGRID): if self.getGemByPos(x, y).rect.collidepoint(*position): return [x, y] return None
我们需要将鼠标连续选择的拼图块进行位置交换，代码实现如下：
def swapGem(self, gem1_pos, gem2_pos): margin = gem1_pos[0] - gem2_pos[0] + gem1_pos[1] - gem2_pos[1] if abs(margin) != 1: return False gem1 = self.getGemByPos(*gem1_pos) gem2 = self.getGemByPos(*gem2_pos) if gem1_pos[0] - gem2_pos[0] == 1: gem1.direction = 'left' gem2.direction = 'right' elif gem1_pos[0] - gem2_pos[0] == -1: gem2.direction = 'left' gem1.direction = 'right' elif gem1_pos[1] - gem2_pos[1] == 1: gem1.direction = 'up' gem2.direction = 'down' elif gem1_pos[1] - gem2_pos[1] == -1: gem2.direction = 'up' gem1.direction = 'down' gem1.target_x = gem2.rect.left gem1.target_y = gem2.rect.top gem1.fixed = False gem2.target_x = gem1.rect.left gem2.target_y = gem1.rect.top gem2.fixed = False self.all_gems[gem2_pos[0]][gem2_pos[1]] = gem1 self.all_gems[gem1_pos[0]][gem1_pos[1]] = gem2 return True
每一次交换拼图块时，我们需要判断是否有连续一样的三个及以上拼图块，代码实现如下：
def isMatch(self): for x in range(NUMGRID): for y in range(NUMGRID): if x + 2 < NUMGRID: if self.getGemByPos(x, y).type == self.getGemByPos(x+1, y).type == self.getGemByPos(x+2, y).type: return [1, x, y] if y + 2 < NUMGRID: if self.getGemByPos(x, y).type == self.getGemByPos(x, y+1).type == self.getGemByPos(x, y+2).type: return [2, x, y] return [0, x, y]
当出现三个及以上拼图块时，需要将这些拼图块消除，代码实现如下：
def removeMatched(self, res_match): if res_match[0] > 0: self.generateNewGems(res_match) self.score += self.reward return self.reward return 0
将匹配的拼图块消除之后，我们还需要随机生成新的拼图块，代码实现如下：
def generateNewGems(self, res_match): if res_match[0] == 1: start = res_match[2] while start > -2: for each in [res_match[1], res_match[1]+1, res_match[1]+2]: gem = self.getGemByPos(*[each, start]) if start == res_match[2]: self.gems_group.remove(gem) self.all_gems[each][start] = None elif start >= 0: gem.target_y += GRIDSIZE gem.fixed = False gem.direction = 'down' self.all_gems[each][start+1] = gem else: gem = Puzzle(img_path=random.choice(self.gem_imgs), size=(GRIDSIZE, GRIDSIZE), position=[XMARGIN+each*GRIDSIZE, YMARGIN-GRIDSIZE], downlen=GRIDSIZE) self.gems_group.add(gem) self.all_gems[each][start+1] = gem start -= 1 elif res_match[0] == 2: start = res_match[2] while start > -4: if start == res_match[2]: for each in range(0, 3): gem = self.getGemByPos(*[res_match[1], start+each]) self.gems_group.remove(gem) self.all_gems[res_match[1]][start+each] = None elif start >= 0: gem = self.getGemByPos(*[res_match[1], start]) gem.target_y += GRIDSIZE * 3 gem.fixed = False gem.direction = 'down' self.all_gems[res_match[1]][start+3] = gem else: gem = Puzzle(img_path=random.choice(self.gem_imgs), size=(GRIDSIZE, GRIDSIZE), position=[XMARGIN+res_match[1]*GRIDSIZE, YMARGIN+start*GRIDSIZE], downlen=GRIDSIZE*3) self.gems_group.add(gem) self.all_gems[res_match[1]][start+3] = gem start -= 1
之后反复执行这个过程，直至耗尽游戏时间，游戏结束。
最后，我们动态看一下游戏效果。
本文我们使用 Python 实现了一个简单的消消乐游戏，有兴趣的可以对游戏做进一步扩展，比如增加关卡等。
到此这篇关于Python实现消消乐小游戏的文章就介绍到这了，希望大家以后多多支持好二三四！